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Ruiya is a Singapore Primary School Math tutor that guides your child step-by-step — it doesn't just hand over the answer. Think of it as a support layer between school and tuition.

Snap a photo or type your child's stuck question and watch how Ruiya helps them work it out.

You get 5 free turns. 1 turn = 1 message from your child + 1 reply from Ruiya. A step-by-step guided problem can use a few turns, so 5 turns is usually enough for 2–3 real homework questions. Photos are welcome.

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Example question

See exactly how Ruiya explains a real question

Mr Raju wanted to divide 42 apples and 60 oranges equally into as many baskets as possible. The number of apples in each basket was the same. Each basket had the same number of fruits. How many fruits were there in each basket?

Mr Raju wants to share both the apples and the oranges into the greatest possible number of baskets, with no fruits left over and each basket having the same number of fruits. This means the number of baskets must be a common factor of both 42 and 60. To get as many baskets as possible, we need to find the Highest Common Factor (HCF). Step 1: Find the factors of 42 and 60 by making a list. Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42 Factors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60 The common factors are 1, 2, 3, and 6. The greatest common factor is 6, so Mr Raju can make 6 baskets. Step 2: Find the number of fruits in each basket. Number of apples in each basket: 42 ÷ 6 = 7 apples Number of oranges in each basket: 60 ÷ 6 = 10 oranges Total number of fruits in each basket: 7 + 10 = 17 fruits (We can also find the total fruits first: 42 + 60 = 102 fruits, then 102 ÷ 6 = 17 fruits!) There were 17 fruits in each basket.